(x-10)^2/3=-6

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Solution for (x-10)^2/3=-6 equation: 


x in (-oo:+oo)

((x-10)^2)/3 = -6 // + 6

((x-10)^2)/3+6 = 0

((x-10)^2)/3+(3*6)/3 = 0

(x-10)^2+3*6 = 0

x^2-20*x+118 = 0

x^2-20*x+118 = 0

x^2-20*x+118 = 0

DELTA = (-20)^2-(1*4*118)

DELTA = -72

DELTA < 0

1 = 0

1/3 = 0

1/3 = 0 // * 3

1 = 0

1 = 0

x belongs to the empty set

x belongs to the empty set

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